Question
The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively. If the percentage yield of Cl2 is 72%, what is its actual yield?
Asked by: USER2626
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Answer (192)
The actual yield is 43 g Cl₂.
The limiting reactant was MnO₂ because it gave the smaller mass of Cl₂.
∴ The theoretical yield is 60.25 g Cl₂.
% yield = actual yield/theoretical yield × 100 %
Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g
Answer: 43 g
took test