The sum of three consecutive integers is 72. Find the integers

a: 23, 24, 25

b: 25, 26, 27

c: 24, 25, 26

d: 22, 23, 24

Let's make an equation.
x+y+z=72
X will be the smallest number. Since they are consecutive, one number is one greater and the other is two greater. Let's make equation for y and z.
x+1=y; the middle number.
x+2=z; the greatest number.
Let's plug these in the equation.
x+x+1+x+2=72
Let's add like terms.
3x+3=72
Subtract 3.
3x=69
Now divide.
69÷3=23
So, the smallest number is 23. So, it must be set a. Let's check.
23+24=47+25=72
So, set a is the correct answer.