Question
Bon jour,resoudre l'équation suivante :(4x-1)au carré-3(2x+7)=(2x-3)(8x+5). Aidez moi svp merci d'avance
Asked by: USER7624
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109 Answers
Answer (109)
(4x-1)²-3(2x+7)=(2x-3)(8x+5)
(4x-1)²-3(2x+7)-(2x-3)(8x+5)=0
16x²-8x+1-6x-21-(16x²+10x-24x-15)=0
16x²-14x-20-16x²-10x+24x+15=0
16x²-14x-20-16x²+14x+15=0
-20+15=0
-5=0
s=Ф
s=(ensemble vide )
(4x-1)²-3(2x+7)-(2x-3)(8x+5)=0
16x²-8x+1-6x-21-(16x²+10x-24x-15)=0
16x²-14x-20-16x²-10x+24x+15=0
16x²-14x-20-16x²+14x+15=0
-20+15=0
-5=0
s=Ф
s=(ensemble vide )