Bonjour pouvez m'aider pour cette exercice svp merci .Le noeud est une correspondant à 1,852 km.h -1 . Le 9 février 2005 ,le voilier l'hydroptère a traversé la manche en 34minutes à la vitesse moyenne de 33 noeuds . Calculer une valeur approchée par excès au km près de la distance parcourue par le voilier

By: USER5496
26 Agustus 2025 mathematiques 5 minutes
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Grade: Education Subject: mathematiques
Bonjour pouvez m'aider pour cette exercice svp merci .Le noeud est une correspondant à 1,852 km.h -1 . Le 9 février 2005 ,le voilier l'hydroptère a traversé la manche en 34minutes à la vitesse moyenne de 33 noeuds . Calculer une valeur approchée par excès au km près de la distance parcourue par le voilier
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bonjour


33 noeuds = 33 x 1.852 = 61.116  km/h

distance = vitesse x temps  

61.116 x 0.57 = 35 km 
Answered on 26 Agustus 2025

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