Question
Bonjour à tous,
Est-ce que quelqu'un aurait la gentillesse de m'aider pour cet exercice svp ?
Ex 1 :
Résoudre les équations ci-dessous
a) (3x-15) (7x+2) = 0
b) (3x-2) (5x-1) - (3x-2) (3x+4) = 0
c) 36x² + 12x + 1 = 0
d) x² - 64 = 0
Merci beaucoup.
Est-ce que quelqu'un aurait la gentillesse de m'aider pour cet exercice svp ?
Ex 1 :
Résoudre les équations ci-dessous
a) (3x-15) (7x+2) = 0
b) (3x-2) (5x-1) - (3x-2) (3x+4) = 0
c) 36x² + 12x + 1 = 0
d) x² - 64 = 0
Merci beaucoup.
Asked by: USER4232
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Answer (311)
Bonjour,
a) (3x - 15) (7x + 2) = 0
3x - 15 = 0 ou 7x + 2 = 0
3x = 15 ou 7x = -2
x = 15/3 ou x = -2/7
x = 5 ou x = -2/7
S = {5 ; -2/7}
b) (3x - 2) (5x - 1) - (3x - 2) (3x + 4) = 0
(3x - 2)[(5x - 1) - (3x + 4)] = 0
(3x - 2)(5x - 1 - 3x - 4) = 0
(3x - 2)(2x - 5) = 0
3x - 2 = 0 ou 2x - 5 = 0
3x = 2 ou 2x = 5
x = 2/3 ou x = 5/2
x = 2/3 ou x = 2,5
S = {2/3 ; 2,5}
c) 36x² + 12x + 1 = 0
(6x + 1)² = 0
6x + 1 = 0
6x = -1
x = -1/6
S = {-1/6}
d) x² - 64 = 0
x² - 8² = 0
(x + 8)(x - 8) = 0
x + 8 = 0 ou x - 8 = 0
x = -8 ou x = 8
S = {-8 ; 8}
a) (3x - 15) (7x + 2) = 0
3x - 15 = 0 ou 7x + 2 = 0
3x = 15 ou 7x = -2
x = 15/3 ou x = -2/7
x = 5 ou x = -2/7
S = {5 ; -2/7}
b) (3x - 2) (5x - 1) - (3x - 2) (3x + 4) = 0
(3x - 2)[(5x - 1) - (3x + 4)] = 0
(3x - 2)(5x - 1 - 3x - 4) = 0
(3x - 2)(2x - 5) = 0
3x - 2 = 0 ou 2x - 5 = 0
3x = 2 ou 2x = 5
x = 2/3 ou x = 5/2
x = 2/3 ou x = 2,5
S = {2/3 ; 2,5}
c) 36x² + 12x + 1 = 0
(6x + 1)² = 0
6x + 1 = 0
6x = -1
x = -1/6
S = {-1/6}
d) x² - 64 = 0
x² - 8² = 0
(x + 8)(x - 8) = 0
x + 8 = 0 ou x - 8 = 0
x = -8 ou x = 8
S = {-8 ; 8}