Question
On donne: D=(2x-3)(5-x)+(2x-3)²
merci
merci
Asked by: USER1192
49 Viewed
49 Answers
Answer (49)
Développer :
(2x - 3) (5 - x) + (2x - 3)²
= 10x - 2x² - 15 + 3x + 4x² - 12x + 9
= - 2x² + 4x² + 10x + 3x - 12x - 15 + 9
= 2x² + x - 6
Factoriser :
(2x - 3) (5 - x) + (2x - 3)²
= (2x - 3) [(5 - x) + (2x - 3)]
= (2x - 3) (5 - x + 2x - 3)
= (2x - 3) (x + 2)
(2x - 3) (5 - x) + (2x - 3)²
= 10x - 2x² - 15 + 3x + 4x² - 12x + 9
= - 2x² + 4x² + 10x + 3x - 12x - 15 + 9
= 2x² + x - 6
Factoriser :
(2x - 3) (5 - x) + (2x - 3)²
= (2x - 3) [(5 - x) + (2x - 3)]
= (2x - 3) (5 - x + 2x - 3)
= (2x - 3) (x + 2)
bonjour
tu ne donnes pas de consigne mais je suppose qu'il faut factoriser
d = ( 2 x - 3) ( 5 - x + 2 x -3)
d = ( 2 x -3) ( x + 2)
tu ne donnes pas de consigne mais je suppose qu'il faut factoriser
d = ( 2 x - 3) ( 5 - x + 2 x -3)
d = ( 2 x -3) ( x + 2)