Va rogg 1)Efectuati , respectand ordinea efectuarii operatiilor : (3x-1)²-2(x+2)²+3(1-x)(1+x)2) Aratati ca : (x-2)(x+2)(x²+4)(x la puterea 4 +16 )(x la puterea 8 +256) = x la puterea 16 +2 la puterea 16

 (3x-1)²-2(x+2)²+3(1-x)(1+x)=
=9x²-6x+1-2(x²+4x+4)+3-3x²=
=9x²-6x+1-2x²-8x-8+3-3x²=
=4x²-14x+4=
=2(2x²-7x+2)

Aratati ca : (x-2)(x+2)(x²+4)(x⁴+16 )(x⁸ +256) = x¹⁶ -2¹⁶
 (x-2)(x+2)(x²+4)(x⁴+16 )(x⁸ +256) = (x²-4)(x²+4)(x⁴+16 )(x⁸ +256) =
= (x⁴-16)(x⁴+16 )(x⁸ +256) = (x⁸-2⁸)(x⁸ +2⁸) =x¹⁶-2¹⁶